Hard
Question
A particle is projected from a point on the ground with an initial velocity of u = 50 m/s at an angle of 53o with the horizontal (tan 53o = 4/3, g = 10 m/s2 = acceleration due to gravity).
Options
A.The velocity of the particle will make angle 45o with the horizontal after time 1 s.
B.The velocity of the particle will make angle 45o with the horizontal after time 7 s.
C.The average velocity between the point of projection and the highest point on its path is horizontal.
D.The average velocity between the point of projection and the highest point on its path is horizontal.
Solution
When particle makes angle 45o with the horizontal.
vy = ± vx
u sin 53o − gt = ± u cos 53o
⇒ t =
∴ t =
= 1 s and t = 
= 7s
vy = ± vx
u sin 53o − gt = ± u cos 53o
⇒ t =
∴ t =
= 1 s and t = = 7sCreate a free account to view solution
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