KinematicsHard
Question
A ball is projected from a certain point on the surface of a planet at a certain angle with the horizontal surface. The horizontal and vertical displacement x and y varies with time t in second as:
x = 10 and y = 10 √3t − t2
The maximum height attained by the ball is
x = 10 and y = 10 √3t − t2
The maximum height attained by the ball is
Options
A.100m
B.75 m
C.50 m
D.25 m
Solution
(Ymax) ⇒ 
⇒
(10 t − t2) = 10 − 2 t ⇒ t = 5
⇒ Ymax = 10(5) − 52 = 25 m Ans ″D″
⇒
(10 t − t2) = 10 − 2 t ⇒ t = 5⇒ Ymax = 10(5) − 52 = 25 m Ans ″D″
Create a free account to view solution
View Solution FreeMore Kinematics Questions
A projectile is thrown with a speed v at an angle θ with the vertical. Its average velocity between the instants it...The acceleration - time graph of a particle moving along a straight line is as shown in figure. At what time particle ac...The velocity of a particle projected from the ground with initial velocity u, making angle q with the horizontal after t...A student uses a simple pendulum of exactly 1m length to determine g, the acceleration due to gravity. He uses a stop wa...A weightless inextensible rope rest on a stationary wee forming an angle with the horizontal. One end moving to the rope...