KinematicsHard

Question

A ball is horizontally projected with a speed v from the top of a plane inclined at an angle 45o with the horizontal. How far from the point of projection with the ball strike the plane?

Options

A.
B.
C.
D.

Solution


R =
Putting      β = 45o & α = π −
R =
sx =
(−ve sign indicates that the displacement is in −ve x direction)
⇒    Range                    Ans ″D″
Alternate II method

β = −     & α =
R =
=
R = (along +ve x die.)
III Method

ux = u cos β ,    T  = , ax =  g sin β ;    ay = − cos β
sx = ux t  + axt2         = (u cos β)
Let α = β = 45o   
So sx = = 
Ans ″D″

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