Hard
Question
A ball is horizontally projected with a speed v from the top of a plane inclined at an angle 45o with the horizontal. How far from the point of projection with the ball strike the plane?
Options
A.
B.
C.
D.
Solution
R =
Putting β = 45o & α = π −
R =
sx =
(−ve sign indicates that the displacement is in −ve x direction)
⇒ Range
Ans ″D″Alternate II method
β = −
& α = 
R =
=
R =
(along +ve x die.)III Method
ux = u cos β , T =
, ax = g sin β ; ay = − cos βsx = ux t +
axt2 = (u cos β) 
Let α = β = 45o
So sx =
= 
Ans ″D″
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