Hard

Question

A body is projected horizontally from the top of a tower with initial velocity 18 ms-1. It hits the ground at angle 45o. What is the vertical component of velocity when it strikes the ground?  

Options

A.18√2 ms-1   
B.18  ms-1   
C.9√2 ms-1   
D.9 ms-1   

Solution

tan45o =

⇒ vy = vx = 18m/s  Ans.

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