Laws of MotionHard
Question
A free 238U nucleus kept in a train emits an alpha particle. When the train is stationary, a nucleus decays and the distance between a particle and the recoiling nucleus becomes x at time t after the decay. If the decay takes place while the train is moving at a uniform velocity v, the distance between the alpha particle and the recoiling nucleus at a time t after the decay as ,measured by the passenger is
Options
A.x + vt
B.x − vt
C.x
D.depends on the direction of the train.
Solution
For observer in train both the situations are same.
Create a free account to view solution
View Solution FreeMore Laws of Motion Questions
Two masses of 10 kg and 5 kg are suspended from a fixed support as shown in figure. The system is pulled down with a for...A astronaut accidentally gets separated out of his small spaceship accelerating in inter-stellar space at a constant acc...A jar containing water is placed in a train. The train accelerates from left to right. Which of the following shows the ...A body of mass m1,exerts a force on another body of mass m2, If the magnitude of acceleration of m2 is a2, then the magn...The frictional force of the air on the body of mass 0.25 kg, falling with an accleration of 9.2 m/s2, will be :...