Laws of MotionHard
Question
A free 238U nucleus kept in a train emits an alpha particle. When the train is stationary, a nucleus decays and the distance between a particle and the recoiling nucleus becomes x at time t after the decay. If the decay takes place while the train is moving at a uniform velocity v, the distance between the alpha particle and the recoiling nucleus at a time t after the decay as ,measured by the passenger is
Options
A.x + vt
B.x − vt
C.x
D.depends on the direction of the train.
Solution
For observer in train both the situations are same.
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