Laws of MotionHard
Question
A person standing on the floor of an elevator drops a coin. The coin reaches the floor of the elevator in time t1 when elevator is stationary and in time t2 if it is moving uniformly. Then
Options
A.t1 = t2
B.t1 > t2
C.t1 > t2
D. t1 < t2 or t1 > t2 depending upon that elevator is moving upwards or downwards
Solution
(A) 
h = 
gt12 ......(1)
Relative to left urell = o arell = g - o = g
srell = urell t2 + 1/2 arell
srell = h ∴ h =
gt22 ....(2)
By (1) & (2)
gt12 = 
gt22 ⇒ [t1 = t2]
h = gt12 ......(1)Relative to left urell = o arell = g - o = g
srell = urell t2 + 1/2 arell
srell = h ∴ h =
gt22 ....(2)By (1) & (2)
gt12 = gt22 ⇒ [t1 = t2]Create a free account to view solution
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