Laws of MotionMedium
Question
Two blocks of masses 10 kg and 20 kg are connected by a light spring as shown. A force of 200 N acts on the 20 kg mass as shown. At a certain instant the acceleration of 10 kg mass is 12 ms-2 towards right direction.
Options
A.At that instant the 20 kg mass has an acceleration of 12 ms-2.
B.At that instant the 20 kg mass has an acceleration of 4 ms-2 .
C.The stretching force in the spring is 120 N.
D.The collective system moves with a common acceleration of 30 ms-2 when the extension in the connecting spring is the maximum.
Solution
Apply NLM on the system
200 = 20 a + 12 × 10
= a = 4 m/s2 spring Force = 10 × 12 = 120 N
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