Laws of MotionMedium

Question

Two blocks A and B of mass 10 kg and 40 kg are connected by an ideal string as shown in the figure. Neglect the masses of the pulleys and effect of friction. (g = 10 m/s2)

Options

A.The acceleration of block A is ms-2
B.The acceleration of block B is α ms-2
C.The tension in the string is N
D.The tension in the string is N

Solution


By string constraint 
aA = 2aB  ................................(1)
equation for block A.
        10 × 10 × − T = 10 aA  ......(2)
equation for block B.
        2T − =  40 aB .........................(3)
Solving equation (1) , (2) & (3)   we get
         aA = m/s2
         aB = m/s2
          T = N

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