Laws of MotionHard

Question

A trolley of mass 8 kg is standing on a frictionless surface inside which an object of mass 2 kg is suspended. A constant force F starts acting on the trolley as a result of which the string stood at an angle of 37o from the vertical (bob at rest relative to trolley) Then :

Options

A.acceleration of the trolley is 40/3 m/sec2.
B.force applied is 60 N
C.force applied is 75 N
D.tension in the string is 25 N

Solution


F.B.D. of trolley is w.r.t. ground
F.B.D. of suspended mass is w.r.t. Trolley.
T cos 37o − mg = 0     [Equilibrium of mass in y direction w.r.t. trolley]
⇒    T =         T = 25 N
T sin 37o − ma = 0     [Equilibrium of mass in x direction w.r.t. trolley]
⇒    a =         =
F − T sin37 = 8a         [Newton′s II law for trolley in x direction w.r.t. ground]
⇒    F = 8 × + 25 × F = 75 N

Create a free account to view solution

View Solution Free
Topic: Laws of Motion·Practice all Laws of Motion questions

More Laws of Motion Questions

Three masses of 1 kg , 6 kg and 3 kg are connected to each other with threads and are placed on table as shown in figure...A balloon of mass M is descending at a constant acceleration α. When a mass m is released from the balloon it start...A force of magnitude F1 acts on a particle so as to accelerate it from rest to a velocity v. The force F1 is then replac...A sphere of mass m is kept in equilibrium with the help of several springs as shown in the figure. Measurement show that...There force F1,F2and F3 act on an object simultaneously. There force vectors are shown are shown in the following free-b...