Laws of MotionHard
Question
Two masses of 10 kg and 20 kg respectively are connected by a massless spring as shown in figure. A force of 200 N acts on the 20 kg mass at the instant when the 10 kg mass has an acceleration of 12 ms-2 towards right, the acceleration of the 20 kg mass is :
Options
A.2 ms-2
B.4 ms-2
C.10 ms-2
D.20 ms-2
Solution
F = m1a1 + m2a2 [Newton′s law for system]
200 = 10 × 12 + 20 × a a = 4 m/s2.
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