Laws of MotionMedium
Question
In other to raise a mass of 100 kg a man of mass 60 kg fasten a rope over a smooth pulley. He climbs the rope with an acceleration 5 g/4 relative to rope. the tension in the rope is (g = 10 m/s2)
Options
A.1432 N
B.928 N
C.1218 N
D.642 N
Solution
amR = 
↑ = am - (- aR)
∴ am =
∴ T - 600 = 60 ×
& T - 100 = 100 aR
By solving we get tension = 1218 N
↑ = am - (- aR)∴ am =
∴ T - 600 = 60 ×
& T - 100 = 100 aR
By solving we get tension = 1218 N
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