Laws of MotionHard
Question
The length of a spring is α when a force of 4 N is applied on it and the length is β when 5 N force is applied. Then the length of spring when 9 N force is applied is -
Options
A.5β - 4α
B.β - α
C.5α - 4β
D.9(α - β)
Solution
Let the natural length of the spring = l0
From figure
4 = k(α - l0)........(i)
5 = k (β - l0).......(ii)
9 = k (γ - l0)........(iii)
e.q
γ = 5β - 4α
From figure
4 = k(α - l0)........(i)
5 = k (β - l0).......(ii)
9 = k (γ - l0)........(iii)
e.q
γ = 5β - 4α
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