NEETPhotoelectric EffectHard
Question
In a fission reaction
23692U
117X + 117Y + n + n
the average binding energy per nucleon of X and Y is 8.5 MeV whereas that of 236U is 7.6 MeV. The total energy liberated will be about :
23692U
117X + 117Y + n + nthe average binding energy per nucleon of X and Y is 8.5 MeV whereas that of 236U is 7.6 MeV. The total energy liberated will be about :
Options
A.200 keV
B.2 MeV
C.2 MeV
D.200 MeV
Solution
Q = (BEx + BEy − Beu)
= (2 × 117 × 8.5 − 236 × 7.6) MeV = 195 MeV ≈ 200 MeV.
= (2 × 117 × 8.5 − 236 × 7.6) MeV = 195 MeV ≈ 200 MeV.
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