Photoelectric EffectHard
Question
This question has Statement - 1 and Statement - 2. Of the four choices given after the statements, choose the one that best describes the two statements.
Statement-1 : A metallic surface is irradiated by a monochromatic light of frequency v > v0 (the threshold frequency). The maximum kinetic energy and the stopping potential are Kmax and V0 respectively. If the frequency incident on the surface doubled, both the Kmax and V0 are also doubled.
Statement-2 : The maximum kinetic energy and the stopping potential of photoelectrons emitted from a surface are linearly dependent on the frequency of incident light.
Statement-1 : A metallic surface is irradiated by a monochromatic light of frequency v > v0 (the threshold frequency). The maximum kinetic energy and the stopping potential are Kmax and V0 respectively. If the frequency incident on the surface doubled, both the Kmax and V0 are also doubled.
Statement-2 : The maximum kinetic energy and the stopping potential of photoelectrons emitted from a surface are linearly dependent on the frequency of incident light.
Options
A.Statement-1 is true, Statement-2 is true; Statement-2 is the correct explanation of Statement-1.
B.Statement-1 is true, Statement-2 is true; Statement-2 is not the correct explanation of Statement-1.
C.Statement-1 is false, Statement-2 is true.
D.Statement-1 is true, Statement-2 is false.
Solution
KEmax = hv - hv0
hv - hv0 = e × ᐃv
V0 =
′v′ is doubled
KEmax = 2hv - hv0
V0′ = (ᐃv)′ =
⇒
may not be equal to 2
⇒
may not equal to 2
KEmax = hv - hv0
hv - hv0 = e × ᐃv
V0 =
′v′ is doubledKEmax = 2hv - hv0
V0′ = (ᐃv)′ =
⇒
may not be equal to 2⇒
may not equal to 2KEmax = hv - hv0
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