Photoelectric EffectHard
Question
A proton and an electron are accelerated by the same potential difference. Let λe and λp denote the de Broglie wavelengths of the electron and the proton respectively.
Options
A.λe = λp
B.λe < λp
C.λe > λp
D.λe and λp depends on the accelerating potential difference.
Solution
Charge present on both panticle are same
∵ λ =
So q1 = q2
> 1
∵ mP > > me
∴ λe > λP
∵ λ =
∵ mP > > me
∴ λe > λP
Create a free account to view solution
View Solution FreeMore Photoelectric Effect Questions
According to De Broglie, wavelength of electron in second orbit is 10-9 metre. Then the circumfrance of orbit is :-...Graph is plotted between maximum kinetic energy of electron with frequency of incident photon in Photo electric effect. ...In an x-ray tube the voltage applied is 20KV. The energy required to remove an electron from L shell is 19.9 KeV. In the...The energy difference between the first two levels of hydrogen atom is 10.2 eV. What is the corresponding energy differe...A radio station is broadcasting the waves of wave length 300 meter. If the radiating power of transmitter is 10 kW, then...