Photoelectric EffectMedium
Question
If the frequency of light in a photoelectric experiment is doubled then maximum kinetic energy of photo electron
Options
A.be doubled
B.be halved
C.become more than double
D.become less than double
Solution
Einstein′s formula
kmax 1 = eV1 + φ
if frequency is doubled,
kmax 2 = eV2 + φ > 2 Kmax 1
kmax 1 = eV1 + φ
if frequency is doubled,
kmax 2 = eV2 + φ > 2 Kmax 1
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