KTGMedium
Question
One mole of an ideal gas is kept enclosed under a light piston (area=10-2 m2) connected by a compressed spring (spring constant 100 N/m). The volume of gas is 0.83 m3 and its temperature is 100K. The gas is heated so that it compresses the spring further by 0.1 m. The work done by the gas in the process is: (Take R = 8.3 J/K-mole and suppose there is no atmosphere).
Options
A.3 J
B.6 J
C.9 J
D.1.5 J
Solution
Before heating let the pressure of an ideal gas be P1 from the equilibrium piston,
P1A = kx1 [For equilibrium position]
∴ x1 =
= 0.1 m
Since during heating process,
The spring is compressed further by 0.1 m
∴ x2 = 0.2 m
work done by gas =
.100(0.22 − 0.12) = .100.(0.1) (0.3)
= 1.50 = 1.5 J
P1A = kx1 [For equilibrium position]
∴ x1 =
= 0.1 m
Since during heating process,
The spring is compressed further by 0.1 m
∴ x2 = 0.2 m
work done by gas =
.100(0.22 − 0.12) = .100.(0.1) (0.3) = 1.50 = 1.5 J
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