KTGHard
Question
For an ideal gas :
Options
A.the change in internal energy in a constant pressure process from temperature T1 to T2 is equal to nCv(T2 − T1), where Cv is the molar specific heat at constant volume and n the number of moles of the gas.
B.the change in internal energy of the gas and the work done by the gas are equal in magnitude in an adiabatic process.
C.the internal energy does not change in an isothermal process.
D.no heat is added or removed in an adiabatic process.
Solution
For any process ᐃU = n CV ᐃT, For Isothermal ᐃT = 0
or U = constant
ᐃQ = 0 (For adiabatic process)
∴ ᐃU + W = 0
ᐃU = − W
or U = constant
ᐃQ = 0 (For adiabatic process)
∴ ᐃU + W = 0
ᐃU = − W
Create a free account to view solution
View Solution FreeMore KTG Questions
An ideal gas at 1 atmospheric pressure and at 273 K has 22.4 litre of volume. This is heated to 546 K and then by applyi...The adiabatic bulk modulus of hydrogen gas (γ = 1.4) at NTP is :...On increasing the temperature of a gas filled in a closed container by 1oC its pressure increases by 0.4%, initial tempe...Two containers A and B contain molecular gas at same temperature with mases of melecules are mA and mB, then relation of...The temperature of H2 and N2 are respectively 300 K and 450 K. The ratio of their average kinetic energies will be:-...