KTGMedium
Question
In figure, an ideal gas is expanded from volume V0 to 2V0 under three different processes. Process 1 is isobaric, process 2 is isothermal and process 3 is adiabatic. Let ᐃU1,ᐃU2 and ᐃU3 be the change in internal energy of the gas is
these three processes. Then :
these three processes. Then :
Options
A.ᐃU1 > ᐃU2 > ᐃU3
B.ᐃU1 < ᐃU2 < ᐃU3
C.ᐃU2 < ᐃU1 < ᐃU3
D.ᐃU2 < ᐃU3 < ᐃU1
Solution
Process ...(1) is isobaric
ᐃU1 = ᐃQ − ᐃW = positive
process (2) is isothermal
ᐃU2 = 0
Process (3) is adiabatic
ᐃQ = 0
ᐃU = − ᐃW = negative
∴ ᐃU1 > ᐃU2 > ᐃU3
ᐃU1 = ᐃQ − ᐃW = positive
process (2) is isothermal
ᐃU2 = 0
Process (3) is adiabatic
ᐃQ = 0
ᐃU = − ᐃW = negative
∴ ᐃU1 > ᐃU2 > ᐃU3
Create a free account to view solution
View Solution FreeMore KTG Questions
Relation between pressure (P) and energy density (E) of an ideal gas is -...According to the kinetic theory of gases the rms velocity of moleculas of a gas is proportional to :-...Ideal gas is taken through process shown in figure:...The reason for the absence of atmosphere on moon is that the :...Two containers A and B contain molecular gas at same temperature with mases of melecules are mA and mB, then relation of...