KTGMedium
Question
In a cyclic process shown in the figure an ideal gas is adiabatically taken from B and A, the work done on the gas during the process B → A is 30 J, when the gas is taken from A → B the heat
Options
A.20 J
B.− 30 J
C.50 J
D.− 10 J
Solution
B → A
ᐃQ = 0
0 = − 30 + ᐃU
ᐃUBA = 30 J
∴ ᐃUAB = −ᐃUBA = − 30 J
ᐃQ = 0
0 = − 30 + ᐃU
ᐃUBA = 30 J
∴ ᐃUAB = −ᐃUBA = − 30 J
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