FrictionHard
Question
A 1.5 kg box is initially at rest on a horizontal surface when at t = 0 a horizontal force 
(with t in seconds), is applied to the box. The acceleration of the box as a function of time t is given by :
= 0 for 0 ≤ t ≤ 2.85
= (1.2t − 2.4)î m/s2 for t > 2.85
The coefficient of kinetic friction between the box and the surface is :
(with t in seconds), is applied to the box. The acceleration of the box as a function of time t is given by : = 0 for 0 ≤ t ≤ 2.85= (1.2t − 2.4)î m/s2 for t > 2.85 The coefficient of kinetic friction between the box and the surface is :
Options
A.0.12
B.0.24
C.0.36
D.0.48
Solution
1.8 t − μk 15 = 1.5 (1.2 t − 2.4)
for t = 2.85 sec.
μk = 0.24
for t = 2.85 sec.
μk = 0.24
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