Fluid MechanicsHard
Question
A portion of a tube is shown in the figure. Fluid is flowing from cross-section area A1 to A2. The two cross-sections are at distance ′l′ from each other. The velocity of the fluid at section A2 is
. If the pressures at A1 & A2 are same, then the angle made by the tube with the horizontal will be :
. If the pressures at A1 & A2 are same, then the angle made by the tube with the horizontal will be : Options
A.37o
B.sin-13/4
C.53o
D.none of these
Solution
A1V1 = A2V2 or A × V1 = 2A 
or V1 = 
= ρgl sin θ
⇒
= gl sin θ
on solving sin θ
or V1 = = ρgl sin θ⇒
= gl sin θon solving sin θ
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