JEE AdvancedProbabilityHard

Question

A box contains 11 tickets numbered from 1 to 11. Two tickets are drawn similtaneously at random.
Let E1 denotes the event that the sum of the numbers on the tickets drawn is even and E2 denotes the event that the sum of the numbers on the tickets drawn is odd
Which of the following hold good?

Options

A.P(E1/E2) = P(E2/E1)
B.E1 and E2 are exhaustive
C.P(E2) > P(E1)
D.E1 and E2 are equally likely

Solution

E1 : Both even or both odd
P(E1) =
P(E2)= 1 - P (E1) =
(i) P(E1 / E2) = = 0
P(E2 / E1) = = 0
(ii) E1 and E2 exhaustive
(iii) P(E2) > P(E1)

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