ProbabilityHard
Question
Two aeroplanes I and II bomb a target in succession. The probabilities of I and II scoring a hit correctly are 0.3 and 0.2, respectively. The second plane will bomb only if the first misses the target. The probability that the target is hit by the second plane is
Options
A.0.06
B.0.14
C.0.2
D.0.7
Solution
The desired probability
= 0.7 × 0.2 + (0.7) (0.8) (0.7) (0.2) + (0.7) (0.8) (0.7) (0.8) (0.7) (0.2) + ....
= 0.14 [ 1 + (0.56) + (0.56)2 + ... ]
= 0.14
= 0.7 × 0.2 + (0.7) (0.8) (0.7) (0.2) + (0.7) (0.8) (0.7) (0.8) (0.7) (0.2) + ....
= 0.14 [ 1 + (0.56) + (0.56)2 + ... ]
= 0.14
Create a free account to view solution
View Solution FreeMore Probability Questions
If A and B are two independent events then P (AB) equals-...5 persons entered the lift cabin on the ground floor of an 8 floor building. Suppose that each of them independently and...3 letters are placed in 3 envelopes randomly. The probability that all letters are not in right envelopes is-...If A and B are two independent events, then the probability that only one of A and B occur is-...If X follows a binomial distribution with parameters n = 8 and p = 1/2, then P (| X − 4 | ≤ 2) equals-...