ProbabilityHard
Question
A die is thrown a fixed number of times. If probability of getting even number 3 times is same as the probability of getting even number 4 times, then probability of getting even number exactly once is
Options
A.1/4
B.
C.
D.
Solution
According to the given condition
nC3
= nC4 
, where n is the number of times die is thrown
⇒ nC3 = nC4 ⇒ n = 7
Thus required probability = 7C1
nC3
= nC4 , where n is the number of times die is thrown⇒ nC3 = nC4 ⇒ n = 7
Thus required probability = 7C1
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