Fluid MechanicsMedium
Question
The reading of a spring balance when a block is suspended from it in air is 60 newton. This reading is changed to 40 newton when the block is submerged in water. The specific gravity of the block must be therefore :
Options
A.3
B.2
C.6
D.3/2
Solution
mg = 60 .................(i)
mg − ρivg = 40 .................(ii)
=
or
= 3
where ρ0 = density of the block and ρl = density of the liquid.
mg − ρivg = 40 .................(ii)
where ρ0 = density of the block and ρl = density of the liquid.
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