Permutation and CombinationHard
Question
A gentleman invites a party of m + n (m ≠ n) friends to a dinner & places m at one table and n at another, the table being round. If the clockwise & anticlockwise arrangements are not to be distinguished and assuming sufficient space on both tables, then the number of ways in which he can arrange the guest is
Options
A.
B.
C.
D.none
Solution
First we select m friends for one table is m + nCm and select a table by 2C1 ways.
Now total number of arrangements is
2 (m + nCm) .
⇒ 2 .
= 2 .
Now total number of arrangements is
2 (m + nCm) .
⇒ 2 .
= 2 .
Create a free account to view solution
View Solution FreeMore Permutation and Combination Questions
If n identical dice are rolled, then no. of possible out comes are -...The number of ways to put five letters in five envelopes when any one letter is kept in right envelope and four letters ...There are m apples and n oranges to be placed in a line such that the two extreme fruits being both oranges. Let P denot...In how many ways can a mixed double tennis game be arranged from 7 married couples, if no husband and wife play in the s...nPn is equal to-...