Permutation and CombinationHard
Question
There are m apples and n oranges to be placed in a line such that the two extreme fruits being both oranges. Let P denotes the number of arrangements if the fruits of the same species are different and Q the corresponding figure when the fruits of the same species are alike, then the ratio P/Q has the value equal to :
Options
A.nP2. mPm. (n - 2) !
B.mP2. nPn. (n - 2) !
C.nP2. nPn. (m - 2) !
D.none
Solution
For P → If same species are different
Total number of arragements is nP2 . (m + n - 2) !
For Q → If same species are alike then number of arrangement is
Hence
= nP2 . m! . (n - 2)! = nP2 . mPm . (n - 2)!
Total number of arragements is nP2 . (m + n - 2) !
For Q → If same species are alike then number of arrangement is
Hence
= nP2 . m! . (n - 2)! = nP2 . mPm . (n - 2)! Create a free account to view solution
View Solution FreeMore Permutation and Combination Questions
The number of different proper factors of 3780 is-...If a, b, c, d, e are prime integers, then the number of divisiors of ab2c2de excluding 1 as a factor, is -...The number of words which can be formed by taking two same and two different letters from the letters of the word ′...Passengers are to travel by a double decked bus which can accommodate 13 in the upper deck and 7 in the lower deck. The ...The number of ways in which 8 answer books be arranged so that the best and the worst do not occur together is-...