Permutation and CombinationHard
Question
Molar conductivities
at infinite dilution of NaCl, HCl and CH3COONa are 126.4, 425.9 and 91.0 S cm2 mol-1 respectively.
for CH3COOH will be:
at infinite dilution of NaCl, HCl and CH3COONa are 126.4, 425.9 and 91.0 S cm2 mol-1 respectively.
for CH3COOH will be:Options
A.390.5 S cm2 mol-1
B.425.5 S cm2 mol-1
C.180.5 S cm2 mol-1
D.290.8 S cm2 mol-1
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= 91.0 + 425.9 - 126.4 = 390.5