Permutation and CombinationHard
Question
The number of permutations that can be formed by arranging all the letters of the word ′NINETEEN′ in which no two E′s occur together. is
Options
A.
B.
C.
× 6C3.
× 6C3.D.
× 6C3.
× 6C3.Solution
NINETEEN
⇒ N → 3 : I, T
E → 3
First we arrange the word of N, N, N, I and T
then the number of ways =
.
Now total 6 number of place which are arrange E is 6C3
Hence total number of ways =
. 6C3
⇒ N → 3 : I, T
E → 3
First we arrange the word of N, N, N, I and T
then the number of ways =
. Now total 6 number of place which are arrange E is 6C3
Hence total number of ways =
. 6C3 Create a free account to view solution
View Solution FreeMore Permutation and Combination Questions
The number of ways to make 5 heaps of 3-3 books each from 15 different books a-...How many numbers lying between 100 and 1000 can be formed with the digits 1,2,3,4,5 if the repetition of digits is not a...In how many ways the alphabets of the word ′MULTIPLE′ can be ordered other than itself, when the order of vo...The number of ways in which 3 persons can occupy 6 rooms separately is-...The total number of words which can be formed using all the letters of the word ″AKSHI″ if each word begins ...