Permutation and CombinationHard
Question
The number of permutations that can be formed by arranging all the letters of the word ′NINETEEN′ in which no two E′s occur together. is
Options
A.
B.
C.
× 6C3.
× 6C3.D.
× 6C3.
× 6C3.Solution
NINETEEN
⇒ N → 3 : I, T
E → 3
First we arrange the word of N, N, N, I and T
then the number of ways =
.
Now total 6 number of place which are arrange E is 6C3
Hence total number of ways =
. 6C3
⇒ N → 3 : I, T
E → 3
First we arrange the word of N, N, N, I and T
then the number of ways =
. Now total 6 number of place which are arrange E is 6C3
Hence total number of ways =
. 6C3 Create a free account to view solution
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