Permutation and CombinationHard
Question
Two variants of a test paper are distributed among 12 students. Number of ways of seating of the students in two rows so that the students sitting side by side do not have identical papers & those sitting in the same column have the same paper is:
Options
A.
B.
C.(6 !)2 . 2
D.12 ! × 2
Solution
= total number of required possible is
12C6 × 6! × 6! × 2!
=
× 6 ! × 6! × 2! = 2 × 12!Create a free account to view solution
View Solution FreeMore Permutation and Combination Questions
The number of ways in which first, second and third prize can be distributed among 5 competitors is (no person can get m...How many words can be formed by taking three letters from the letters of the word ′SERIES′ ?...Sum of all the numbers that can be formed using all the digits 2, 3, 3, 4, 4, 4 is -...How many five digit even numbers can be formed by using the digits 0,2,3,4,5 (Rept. not allowed)?...A five letter word is to be formed such that the letters appearing in the odd numbered positions are taken from the lett...