Permutation and CombinationHard

Question

Two variants of a test paper are distributed among 12 students. Number of ways of seating of the students in two rows so that the students sitting side by side do not have identical papers & those sitting in the same column have the same paper is:

Options

A.
B.
C.(6 !)2 . 2
D.12 ! × 2

Solution

= total number of required possible is

12C6 × 6! × 6! × 2!
= × 6 ! × 6! × 2! =  2 × 12!

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