Permutation and CombinationHard
Question
Two variants of a test paper are distributed among 12 students. Number of ways of seating of the students in two rows so that the students sitting side by side do not have identical papers & those sitting in the same column have the same paper is:
Options
A.
B.
C.(6 !)2 . 2
D.12 ! × 2
Solution
= total number of required possible is
12C6 × 6! × 6! × 2!
=
× 6 ! × 6! × 2! = 2 × 12!Create a free account to view solution
View Solution FreeMore Permutation and Combination Questions
50C36 is divisible by...Out of 6 boys and 4 girls a group of 7 is to be formed. How many such groups are possible if boys are to be in majority?...The number of ways in which the number 27720 can be split into two factors which are co-primes, is:...If α = mC2, then αC2 is equal to -...In a unique hockey series between India & Pakistan, they decide to play on till a team wins 5 matches. The number of way...