Permutation and CombinationHard

Question

Sum of all the numbers that can be formed using all the digits 2, 3, 3, 4, 4, 4, is:

Options

A.22222200
B.11111100
C.55555500
D.20333280

Solution

= = 10
= = 20
= = 30
Hence sum of unit places is
2 × 10 + 3 × 20 + 4 × 30 = 200
Hence required sum is
=  200 × (105 + 104 + 103 + 102 + 101 + 100)
=  200 × (111111) = 22222200

Create a free account to view solution

View Solution Free
Topic: Permutation and Combination·Practice all Permutation and Combination questions

More Permutation and Combination Questions

In a unique hockey series between India & Pakisthan, they decide to play on till a team wins 5 matches. The number of wa...The number of words formed from letters of the word ′EAMCET′ so that no two vowels come together, is-...If n objects are arranged in a row, then the number of ways of selecting three of these objects so that no two of them a...How many divisors of 21600 are divisible by 10 but not by 15?...The number of ways in which n distinct objects can be put into two different boxes is-...