Permutation and CombinationHard
Question
2nPn is equal to
Options
A.(n + 1) ( n + 2) ..... (2n)
B.2n [1 . 3 . 5 .....(2n - 1)]
C.(2) . (6) . (10) .... (4n - 2)
D.n!(2nCn)
Solution
Value of 2npn is 
(i) (n + 1) (n + 2) ----- (2n) and n ! . 2nCn
= 2n (1.3.5.7. .....(2n - 1)) = (2. 6. 10. 14 ..... (4n - 2))
(i) (n + 1) (n + 2) ----- (2n) and n ! . 2nCn
= 2n (1.3.5.7. .....(2n - 1)) = (2. 6. 10. 14 ..... (4n - 2))
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