JEE AdvancedPermutation and CombinationMedium
Question
Number of divisors of the form (4n + 2), n ≥ 0 of the integer 240 is
Options
A.4
B.8
C.10
D.3
Solution
Since, 240 = 24 . 3 . 5
∴ Total number of divisors = (4 + 1)(2)(2) = 20
Out of these 2, 6, 10, and 30 are of the form 4n + 2
Therefore, (a) is the answer.
∴ Total number of divisors = (4 + 1)(2)(2) = 20
Out of these 2, 6, 10, and 30 are of the form 4n + 2
Therefore, (a) is the answer.
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