DeterminantHard

Question

If a, b, c are all different and = 0, then:

Options

A.abc (ab + bc + ca) = a + b + c
B.(a + b + c) (ab + bc + ca) = abc
C.abc (a + b + c) = ab + bc + ca
D.none of these

Solution



abc (a - b) (b - c) (c - a) (ab + bc + ca) = (a - b) (b - c) (c - a) (a + b + c)
∴ abc (ab + bc + ca) = (a + b + c)

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