DeterminantHard
Question
The number of distinct real roots of
= 0 in the interval -
≤ x ≤
is
= 0 in the interval -
≤ x ≤
is Options
A.0
B.2
C.1
D.3
Solution
Given,
= 0
Applying C1 → C1 + C2 + C3

= (cos x + sin x)
Applying R2 → R2 - R1, R3 → R3 - R1
⇒ (2 cos x + sin x)
⇒ (2cos x + sin x)(sin x - cos x)2 = 0
⇒ 2 cos x + sin x = 0 or sin x - cos x = 0
⇒ 2 cos x = - sin x or sin x = cos x
⇒ cot x = - 1/2 gives no solution in -
≤ x ≤ 
and sin x = cos x ⇒ tan x = 1
⇒ x = π / 4
= 0Applying C1 → C1 + C2 + C3

= (cos x + sin x)

Applying R2 → R2 - R1, R3 → R3 - R1
⇒ (2 cos x + sin x)

⇒ (2cos x + sin x)(sin x - cos x)2 = 0
⇒ 2 cos x + sin x = 0 or sin x - cos x = 0
⇒ 2 cos x = - sin x or sin x = cos x
⇒ cot x = - 1/2 gives no solution in -
≤ x ≤ 
and sin x = cos x ⇒ tan x = 1
⇒ x = π / 4
Create a free account to view solution
View Solution FreeMore Determinant Questions
(where i = ) equals -...If A is a square matrix of order 3 and A′ denotes transpose of matrix A, A′ A = I and det A = 1, then det (A...A1 = [ a1]A2 = A3 = ................................An = [....]Where ar = [ log2r ] ([.] denotes greatest integer). Then...The value of the determinant is...The determinant =...