DeterminantHard
Question
If the determinant 
splits into exactly K determinants of order 3, each element of which contains only one term, then the value of K =
splits into exactly K determinants of order 3, each element of which contains only one term, then the value of K =Options
A.6
B.7
C.8
D.9
Solution
Now each det. may splits in 2 det.
So, total determinants are 8.
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