DeterminantHard

Question

The value of θ lying between and 0 ≤ A ≤ and satisfying the equation = 0 are -

Options

A.A = , θ = -
B.A = = 0
C.A = , θ = -
D.A = , θ =

Solution

= 0
C1 → C1 + C2
⇒  = 0
⇒ = 0
⇒ 2(1 + 2sin4θ) - 2sin4θ = 0
⇒  1 + sin4 θ = 0
sin4θ = - 1
4θ = - or 4θ =
θ = - or θ = &  A ∈ R

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