ElectrostaticsHard
Question
Two point charges a & b, whose magnitudes are same are positioned at a certain distance from each other with a at origin. Graph is drawn between electric field strength at points between a & b and distance x from a. E is taken positive if it is along the line joining from a to b. From the graph, it can be decided that
Options
A.a is positive, b is negative
B.a and b both are positive
C.a and b both are negative
D.a is negative, b is positive
Solution
a & b can′t be both +ve or both − ve otherwise field would have been zero at their mid point. b can′t be positive even, otherwise the field would have been in −ve direction to the right of mid point answer is (a)
Create a free account to view solution
View Solution FreeMore Electrostatics Questions
Two particles X and T, of equal mass and with unequal positive charges, are free to move and are initially far away from...Figure represents a square carrying charges +q, +q, -q, -q at its four corners as shown. Then the potential will be zero...If the potential in the region of space near the point (-2, 4, 6)m is V = 80x2 + 60 y2 volt. Then components of electric...A conducting sphere of radius 10 cm is charged with 10 μC. another uncharged sphere of radius 20 cm is allowed to t...An electron of mass m and charge e is accelerated from rest through a potential difference V in vacuum. The final speed ...