ElectrostaticsHard
Question
The volume charge density as a function of distance X from one face inside a unit cube is varying as shown in the figure. Then the total flux (in S.I. units) through the cube if (ρ0 = 8.85 × 10-12 C/m3) is:


Options
A.1/4
B.1/2
C.3/4
D.1
Solution
Net flux through the cube, φnet = 
To find qin, let′s divide the cube into small elements, and consider a small element of width dx as shown.
Charge on the small element = (ρ) (A.dx)
Total charge =

=
= (A) (Area of r − x graph)
= (1)2
=
ρ0.

⇒ Net flux φnet =
=
=
(as ρ0 = 8.85 × 10-12)
To find qin, let′s divide the cube into small elements, and consider a small element of width dx as shown.
Charge on the small element = (ρ) (A.dx)
Total charge =

=
= (A) (Area of r − x graph)
= (1)2
=

⇒ Net flux φnet =
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