ElectrostaticsHard
Question
Two identical particles of mass m carry a charge Q each. Initially one is at rest on a smooth horizontal plane and the other is projected along the plane directly towards first particle from large distance with speed v. The closest distance of approach be :
Options
A.
B.
C.
D.
Solution
By mechanical energy conservation
0 +
mv2 + 0 = 
x2
(∴ from momentum conservation at closet approach, both particle will move with a common speed v/2)
0 +
mv2 + 0 = x2 (∴ from momentum conservation at closet approach, both particle will move with a common speed v/2)
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