ElectrostaticsMedium
Question
A particle A has charge +q and particle B has charge + 4q with each of them having the same mass m. When allowed to fall from rest through same electrical potential difference, the ratio of their speed vA : vB will be :
Options
A.2 : 1
B.1 : 2
C.4 : 1
D.1 : 4
mVA2 = qV, 
mVB2 = 4qV ⇒ ∴ 
⇒ 
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