DeterminantHard
Question
The value of ′k′ for which the set of equations 3x + ky - 2z = 0, x + ky + 3z = 0, 2 x + 3 y - 4 z = 0 has a non - trivial solution over the set of rational is:
Options
A.33/2
B.31/2
C.16
D.15
Solution
3x + ky - 2z = 0
x + ky + 3z = 0
2x + 3y - 4z = 0
ᐃ =
= 0
∴ k = 33/2
x + ky + 3z = 0
2x + 3y - 4z = 0
ᐃ =
= 0∴ k = 33/2
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