DeterminantHard
Question
If F (α) = 
and G (β) =
, then [F (α) G (β)]-1 =
and G (β) =, then [F (α) G (β)]-1 = Options
A.F (α) - G(β)
B.- F (α) - G(β)
C.[F(α)]-1 [G(β)]-1
D.[G(β)]-1 [F(α)]-1
Solution
|F| ≠ 0 and |G| ≠ 0
As we known [AB]-1 = B-1 A-1
∴ [F(α) G(β)]-1 = [G(β)]-1[F(α)]-1
As we known [AB]-1 = B-1 A-1
∴ [F(α) G(β)]-1 = [G(β)]-1[F(α)]-1
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