DeterminantHard
Question
If A is a diagonal matrix of order ′n′ such that A2 = A, then number of possible values of matrix A, is
Options
A.0
B.1
C.2n
D.2n - 1
Solution
A2 = A
⇒ d12 = d1, d22 = d2, .........., dn2 = dn
⇒ di = 1, 0
So number of possible matrices are 2n
⇒ d12 = d1, d22 = d2, .........., dn2 = dn
⇒ di = 1, 0
So number of possible matrices are 2n
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