DeterminantHard

Question

If A is a diagonal matrix of order ′n′ such that A2 = A, then number of possible values of matrix A, is

Options

A.0
B.1
C.2n
D.2n - 1

Solution

A2 = A
⇒   d12 = d1, d22 = d2, .........., dn2 = dn
⇒  di = 1, 0
So number of possible matrices are 2n

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