ElectrostaticsMedium
Question
Figure shows a closed surface which intersects a conducting sphere. If a positive charge is placed at the point P, the flux of the electric field through the closed surface:
Options
A.will become positive
B.will remain zero
C.will become undefined
D.will become negative
Solution
enclosed charge = +ve ⇒ flux through closed surface = +ve.
⇒ Due to induction the charge enclosed in the dotted becomes +ve
Create a free account to view solution
View Solution FreeMore Electrostatics Questions
Two points P and Q are maintained at the potentials of 10V and - 4V respectively. The work done in moving 100 electrons ...Three positive chages of equal value q are placed at the vertices of an equal equuilateral triangle. The resulting lines...Along the positive direction of x-axis there exists a constant electric field E0. If electric potential at x = 0 is zero...A ring of radius R is charged uniformly with a charge + Q . The electric field at any point on its axis at a distance r ...The total flux associated with given cube will be - where ′a′ is side of cube : - ( = 4π × 9 ×...