ElectrostaticsMedium
Question
The electric potential V as a function of distance x (in metre) is given by V = (5x2 + 10x − 9) volt. The value of electric field at x = 1 m would be :
Options
A.- 20 volt/m
B.6 volt/m
C.11 volt/m
D.-23 volt/m
Solution
E = − 
= − 10 x − 10
∴ E(x =1m) − 10 (1) − 10 = − 20 V/m
= − 10 x − 10∴ E(x =1m) − 10 (1) − 10 = − 20 V/m
Create a free account to view solution
View Solution FreeMore Electrostatics Questions
Six point charges are kept at the vertices of a regular hexagon of side L and centre O, as shown in the figure. Given th...For a dipole q = 2 × 10−6 cb ; d = 0.01m find the maximum torque on the dipole if E = 5 × 105 N/C : -...Two infinite sheets carrying charge density + σ and -σ are arranged perpendicularly as shown in the figure. ...Three charges q, 2q and 8q are to be placed on a 9 cm long straight line. Where the charges should be placed so that the...A ring of radius R carries a charge + q A test charge - q0 is released on its axis at a distance√3 R from its cent...