Binomial TheoremHard

Question

is equal to -

Options

A.4n - 3n + 1
B.4n - 3n - 1
C.4n - 3n + 2
D.4n - 3n

Solution


= [rC0 + rC1 . 2 + ....... + rCr - 1 2r - 1]  = (3r - 2r) = 4n - 3n

Create a free account to view solution

View Solution Free
Topic: Binomial Theorem·Practice all Binomial Theorem questions

More Binomial Theorem Questions

The value of $\sum_{k = 1}^{\infty}\mspace{2mu}( - 1)^{k + 1}\left( \frac{k(k + 1)}{k!} \right)$ is :...If Cr stands for nCr, then the sum of the series [Co2 - 2C12 + 3C22 - .... + (- 1)r (n + 1)Cn2] where n is an even posit...In the expansion of -...is equal to (here Cr = 10Cr)...The term independent of x in is -...