Binomial TheoremHard

Question

is equal to -

Options

A.4ⁿ - 3ⁿ + 1

B.4ⁿ - 3ⁿ - 1

C.4ⁿ - 3ⁿ + 2

D.4ⁿ - 3ⁿ

Solution

= [^rC₀ + ^rC₁ . 2 + ....... + ^rC_{r - 1} 2^{r - 1}] = (3^r - 2^r) = 4ⁿ - 3ⁿ

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