ElectroMagnetic InductionHard
Question
In a L-R growth circuit, inductance and resistance used are 1 Henry and 20 Ω respectively. If at t = 50 millisecond, current in the circuit is 3.165 A then applied direct current emf is :
Options
A.200V
B.100V
C.50V
D.Data is insufficient to find out the value.
Solution
Time constant = 1/20 = 50 msec
so i = 0.633 imax = 0.633 E/R ⇒ E =
= 100 V
so i = 0.633 imax = 0.633 E/R ⇒ E =
= 100 VCreate a free account to view solution
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