ElectroMagnetic InductionHard

Question

In the figure shown current i = 10e^-4tA. Value of V_L and V_a - V_b is : -

Options

A.-80 e^-4t, -40 e^-4t

B.80 e^-4t, 10 e^-4t

C.-40 e^-4t, -80 e^-4t

D.Zero, Zero

Solution

V_L = + L = +2(10e^-4t) = -80e^-4t
Now V_a - iR - = V_b
V_a - V_b = iR +
= 40 e^-4t - 80 e^-4t
= - 40 e^-4t

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